- Joined
- Nov 20, 2009
- Messages
- 926
I have a upcoming test on Algebra, math is usually a subject I don't have to much trouble with but this question confuses me. :facewall:
"Wally has a dish full of nickels, dimes and quarters worth a total of $6.50. He has three times as many nickels as dimes, and eight more dimes than quarters. How many of each coin does he have?"
So I did broke it down using one variable. "n" for number of nickels
5n + 1/3(10n) + 1/3(25n) - 8 = 650
So I multiplied by 3/1 to simplify. 15n +10n + 25n - 24 = 1950
50n = 1974
n = 39.48 which rounds to 40
n=40
dimes = 13.3
quarters = 5
But that ends with $4.58 total.
Help would be much appreciated, and I apologize if this is the wrong section.
"Wally has a dish full of nickels, dimes and quarters worth a total of $6.50. He has three times as many nickels as dimes, and eight more dimes than quarters. How many of each coin does he have?"
So I did broke it down using one variable. "n" for number of nickels
5n + 1/3(10n) + 1/3(25n) - 8 = 650
So I multiplied by 3/1 to simplify. 15n +10n + 25n - 24 = 1950
50n = 1974
n = 39.48 which rounds to 40
n=40
dimes = 13.3
quarters = 5
But that ends with $4.58 total.
Help would be much appreciated, and I apologize if this is the wrong section.


















