CS:GO TTT role randomization?

[sushi]

How randomized are the roles? Because I made a new account as an experiment and try to see how many Innocent/Traitor/Detective rounds I got.

 

[Kagato]

Short answer: probably around 60-65% inno, 20-25% traitor, and 10-15% detective.

Long answer:

Spoiler

Your sample size is n=12. It's not representative of the population or statistically significant.

Equivalent example: I flipped a fair coin 12 times and got heads 9 out of the 12 times. That must mean the probability of flipping a heads is 75% right? Not quite. You'd find if you flipped more coins, your probability would get closer and closer to the expected value of 50% i.e., theoretical and experimental probabilities can be different when sample size is small.

where n is your sample size and as

, your distribution becomes normal.

Really long answer:

Spoiler

Get RDM'd nerd

 

[DeerFat]

Short answer: probably around 60-65% inno, 20-25% traitor, and 10-15% detective.

Long answer:

Spoiler

Your sample size is n=12. It's not representative of the population or statistically significant.

Equivalent example: I flipped a fair coin 12 times and got heads 9 out of the 12 times. That must mean the probability of flipping a heads is 75% right? Not quite. You'd find if you flipped more coins, your probability would get closer and closer to the expected value of 50% i.e., theoretical and experimental probabilities can be different when sample size is small.

where n is your sample size and as

, your distribution becomes normal.

Really long answer:

Spoiler

Get RDM'd nerd

I love this post

 

[Kaarma]

Short answer: probably around 60-65% inno, 20-25% traitor, and 10-15% detective.

Long answer:

Spoiler

Your sample size is n=12. It's not representative of the population or statistically significant.

Equivalent example: I flipped a fair coin 12 times and got heads 9 out of the 12 times. That must mean the probability of flipping a heads is 75% right? Not quite. You'd find if you flipped more coins, your probability would get closer and closer to the expected value of 50% i.e., theoretical and experimental probabilities can be different when sample size is small.

where n is your sample size and as

, your distribution becomes normal.

Really long answer:

Spoiler

Get RDM'd nerd

alright nerd

 

[sushi]

Short answer: probably around 60-65% inno, 20-25% traitor, and 10-15% detective.

Long answer:

Spoiler

Your sample size is n=12. It's not representative of the population or statistically significant.

Equivalent example: I flipped a fair coin 12 times and got heads 9 out of the 12 times. That must mean the probability of flipping a heads is 75% right? Not quite. You'd find if you flipped more coins, your probability would get closer and closer to the expected value of 50% i.e., theoretical and experimental probabilities can be different when sample size is small.

where n is your sample size and as

, your distribution becomes normal.

Really long answer:

Spoiler

Get RDM'd nerd

Proof that Kagato likes RDM

 

[Chaonyx]

alright nerd

*mega nerd

 

[Kaarma]

*mega nerd

ok nerd

 

[aspen]

bruh Kagato why you bringing math into this

 

[Chaonyx]

ion science

 

[Buster]

sushi as the kat man said, the more rounds played, the closer to the actual value your numbers will become.

Traitor ~23%
Innocent ~ 64%
Detective ~13%

So realistically it looks like a 20, 65, 15 split.

 

[Lord. Death.]

as far as I know

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Poster Extraordinaire
Senior Manager
Apr 16, 2020
there is already a system is place to combat any issues that there might be with not getting traitor. If you were an innocent or detective the previous round, you get two entries in a player list that it chooses from at round start to receive the traitor role. Without this extra entry you already have a 25% change to get traitor.

 

[Buster]

as far as I know

Now that makes sense to me